Научная статья на тему 'On strongly algebraically closed lattices'

On strongly algebraically closed lattices Текст научной статьи по специальности «Математика»

CC BY
50
9
i Надоели баннеры? Вы всегда можете отключить рекламу.
Ключевые слова
EXISTENTIALLY AND ALGEBRAICALLY CLOSEDLATTICES / STRONGLY ALGEBRAICALLY CLOSEDLATTICES / EQUATIONALLY NOETHERIAN LATTICE / COMPLETE BOOLEAN ALGEBRAS / ЭКЗИСТЕНЦИАЛЬНО И АЛГЕБРАИЧЕСКИ ЗАМКНУТЫЕ РЕШЕТКИ / СИЛЬНО АЛГЕБРАИЧЕСКИ ЗАМКНУТЫЕ РЕШЕТКИ / ЭКВАЦИОНАЛЬНО НЕТЕРОВА РЕШЕТКА / ПОЛНЫЕ БУЛЕВЫ АЛГЕБРЫ

Аннотация научной статьи по математике, автор научной работы — Molkhasi Ali

In this article some fundamental properties of existentially and algebraically closed lattices are investigated. We also define the notion of strongly algebraically closed lattices and we show that a q ′ -compact complete boolean lattice is strongly algebraically closed.

i Надоели баннеры? Вы всегда можете отключить рекламу.
iНе можете найти то, что вам нужно? Попробуйте сервис подбора литературы.
i Надоели баннеры? Вы всегда можете отключить рекламу.

О сильно алгебраически замкнутых решетках

Вэтой статье исследованы некоторые фундаментальные свойства экзистенциальноиалгебраически замкнутых решеток. Определено также понятие сильно алгебраически замкнутой решетки. Показано, что q ′-компактное полная булева решетка сильно алгебраически замкнута.

Текст научной работы на тему «On strongly algebraically closed lattices»

УДК 512.562

On Strongly Algebraically Closed Lattices

Ali Molkhasi*

Faculty of Mathematical Sciences University of Tabriz Tabriz

Iran

Received 01.11.2015, received in revised form 05.01.2016, accepted 18.02.2016 In this article some fundamental properties of existentially and algebraically closed lattices are investigated. We also define the notion of strongly algebraically closed lattices and we show that a q'-compact complete boolean lattice is strongly algebraically closed.

Keywords: existentially and algebraically closed lattices, strongly algebraically closed lattices, equationally noetherian lattice, complete Boolean algebras. DOI: 10.17516/1997-1397-2016-9-2-202-208.

Introduction

Suppose L is an algebraic language and A is an algebra of type L. If we attach the elements of A as constants to L, then the new language will be denoted by L(A). Let X be a class of algebras of type L and A e X. We say that A is existentially closed in the class X, if every existential sentence ^ in the language L(A) which is true in some extension A C B e X, is also true in A. If we restrict ourself to the positive existential sentences, then we obtain the definition of an algebraically closed algebra in the class X. Equivalently, A is existentially closed in X, if and only if every finite set of equations and inequations with coefficients from A, which is solvable in some B e X containing A, already has a solution in A itself. Similarly A is algebraically closed in X, if and only if every finite set of equations with coefficients from A, which is solvable in some B e X containing A, already has a solution in A.

Many articles have already been published concerning the existentially and algebraically closed algebras in several algebraic structures. In a preprint, M. Shahryari investigated some applications of these concepts to special classes of groups (see [5]). In this paper, we focus on distributive lattices. Already, in [4] J.Schmid proved that in the class of distributive lattices, a lattice A is algebraically closed if and only if, it is boolean. Also, he showed that A is existentially closed, if and only if, it is an atomless boolean lattice (see [4]). Schmid asked about the situation in which a distributive lattice is strongly algebraically closed. Note that we say that an algebra A is strongly algebraically closed in a class X, if every set of equations (finite or infinite) with coefficients from A, which is solvable in some B e X containing A, already has a solution in A. In the case of lattices, it is easy to see that such a distributive lattice must be a complete boolean lattice. In this paper, we define the notion of a ^'-compact lattice and we show that if such a lattice is also complete boolean, then it is strongly algebraically closed. The organization of the paper is as follows: in Section 1, we show that if a class X of lattices is inductive and closed under elementary sublattices, then every element of X has an extension which is existentially closed in X. In fact, this result is not new and at least a version of it for classes of groups is presented in [5]. However, in our version, the assumption of being closed under elementary substructures is applied instead of the stronger hypothesis of being closed under substructures.

*a-molkhasi@tabrizu.ac.ir © Siberian Federal University. All rights reserved

In Section 2, we collect some elementary properties of algebraic and existentially closed lattices in some small classes. We also obtain a connection between variants of the property of being equationally noetherian and completeness of distributive lattices. Section 3 consists of a review of some notions of unltraproduct construction and universal algebraic geometry. The last section contains a proof of the main theorem. The reader can consult any standard text of universal algebra and model theory for basic notions of logic, and also any book of lattice theory can be used for elementary definitions of lattices. We will assume that the reader is familiar with free lattices, boolean lattices and algebras and the possibility of extending any distributive lattice to a boolean one.

1. Existentially closed lattices

For lattices A and B we write A < B if A is a sublattice of B and refer to this as an extension of H. An equation with parameters (or coefficients) in lattice A is an expression of the form

f («1, • • • 7 «mi • • • 7 xn ) « g(«i, • • • 7 am7 x 17 • • • 7 xn)

where f7 g are lattice polynomials and a17 ••• 7 am £ A are the parameters. Replacing « by we obtain an inequality (with parameters in A). A finite system of equations and inequations with parameters in A has the form:

S = {fi ~ g17 ••• 7 fm ~ gm7 fm+1 ^ gm+17 ••• 7 fm+n ^ gm+n }•

Note that expressions of the form f < g or f < g may be replaced by f Ag = f or f Ag = f7f^ g, respectively, so there is no need to include such expressions in our considerations. A lattice A is called existentially closed, if any finite consistent system of equations and inequations with coefficients from A, has a solution in A. A system S with coefficients in A is called consistent, if there is an extension B, such that S has a solution in B. One can generalize this definition to an arbitrary class of lattices. Let X be a class of lattices. A lattice A £ X is called existentially closed in the class X, if every X-consistent system S has a solution in A. Here, X-consistency means that there exists a lattice B £ X which contains A and S has a solution in B. Recall that a class of lattices is called inductive, if it contains the union of any chain of its elements. A version of the following lemma which uses of the assumption of being closed under substructure is known at least for classes of groups. But we give a proof for the lattice case with a weaker assumption of being closed under elementary substructure. Also note that, sorts of the lemma and the forthcoming theorem are standard in model theory for elementary classes of first order structures, but the classes used in our versions are not necessarily axiomatizable.

Lemma 1.1. Suppose that X is an inductive class of lattices which is closed under the operation of taking elementary sublattices. Let A £ X. Then there is B £ X which A C B and \B\ ^ max{Ko7 \A\}. Also, for any finite system of equations and inequations S over A, we have either of the following assertions:

(1) S has a solution in B.

(2) For any extension B C C £ X, the system S has no solution in C.

Proof. Let k = max{K07 \A\}. It is clear that the cardinal of the set of all systems of equations and inequations with coefficient A is at most k. So, we can suppose {Sa} is the set of all such systems indexed by ordinals 0 < a < k. Let A0 = A and suppose that AY £ X is previously defined such that \AY \ < k and

¡3 <y Ap C ay • Suppose that Ka = UY<aAY. Since X is inductive, so Ka £ X, also

\Ka\ ^ A \ <

k2 = k•

Y<a

If Sa has no solution in any extension of Ka, then we let Aa = Ka. If there is C e X such that Ka C C and Sa has a solution u = (u1y ..., un) in C we let Aa to be the least elementary sublattice of C containing Ka and the solution u = (u1, ..., un). Note that by Lowenheim-Skolem theorem, we may assume that Aa has the cardinality at most k. Recall that X is closed under elementary sublattice, consequently Aa e X. In this way, for all 0 < a < k the lattice Aa is defined. Also,

¡3 <a Ap C Aa.

Now, we put B = |J Aa e X. This lattice has the desired properties. Because, if a system S = Sa has no solution in B, then it has no solution in any extension of Ka. Therefore, it has no solution in any extension B. □

Theorem 1.2. Suppose that X is an inductive class of lattices closed under elementary sublattice and A e X. Then there is A* e X such that:

(1) A < A*.

(2) A* is existentially closed in class X.

(3) \A*\ < max{Ko, \A\}.

Proof. Assume A0 = A and A1 = B, where B is the lattice already obtained in Lemma 1.1. Now, suppose that Am is already defined and Am+1 is the lattice which its existence is proved in Lemma 1.1 for A = Am. Let

A* = UmAm.

Since X is inductive, so A* e X and as well A* satisfies condition (1) and (2). Suppose that S is a consistent system with coefficients from A*. Since S is finite, so there exists m such that S is system with coefficient in Am. Therefore, S has a solution in Am+1. □

As an application, suppose that X is the class of distributive lattices. Then by the above theorem, every distributive lattice A has an extension B with the cardinality at most max{K0, \A\}, such that B is existentially closed in X. Since by [4] such a lattice is an atomless boolean lattice, so we conclude that every distributive lattice A can be extended to an atomless boolean lattice of the cardinality at most max{K0, \A\}.

2. Existentially closed lattices in small classes

Suppose A is a sublattice of B. Then the class X = {A,B} is inductive. In this section we discuss about the situation in which A is algebraically or existentially closed in X. If this happens, then we simply say that A is algebraically (existentially) closed in B. Recall that a sublattice A of a lattice B is called a retract of B, if there is a homomorphism (termed retraction) ^ : B ^ A which is identity on A. We will show that every retract of B is algebraically closed in B. A similar investigation for the case of groups is done By Miasnikov and Romankov in [3]. Here, we assume that X = {x1,x2,... ,xn} is a finite set of variables, and FL[X] is the free lattice with basis X.

Definition 2.1. A lattice A is called equationally noetherian, if any system of equations with coefficient in A is equivalent with a finite subsystem. If any system of equations over A is equivalent with a finite system then it is said weakly equationally noetherian.

In the following theorem we prove some properties of retracts. This theorem as well as its proof is the lattice version of the similar theorem for groups in [3].

Theorem 2.2. Let A ^ B be a lattice extension. Then the following hold: (1) If A is a retract of B, then A is algebraically closed in B.

(2) Suppose that B is finitely presented and A is finitely generated. Then A is algebraically closed in B if and only if A is a retract.

(3) Suppose that B is finitely generated relative to A and A is equationally noetherian. Then A is algebraically closed in B if and only if A is a retract.

Proof. Suppose that A is a retract of B and y : B ^ A is a retraction. Let

S = {f1 « g17 ••• 7 fm ~ gm}

be a finite system of equations that has a solution b17 • • • 7bn in B. Then one can check that S has a solution y(b1)7 • • • 7 y(bn) in A. This shows that A is algebraically closed in B.

To prove (2), assume that A is generated by a finite set a17 • • • 7«m and B is a finitely presented as B = (b17 • • • 7bn \r1 « s17 • • • 7rk « sk). Every ai can be expressed as a lattice word in letters b 17 • • • 7 bn, so assume that ai = (b17 • • • 7 bn), for i =17 • • • 7 m. Consider the system of equations

¥1(x17 ••• 7 X n) « «17 •• ^ ym(x17 • • • 7 xn) ~ am7

r1(X17 • • • 7 Xn) « S1(X17 • • • 7Xn)7 • • • 7rk (x 1 7 • • • 7 X n) ~ Sk (X1 7 ••• 7 Xn )

with the constants ai £ A. This system has a solution

X1 = b1 7 • • • 7 Xn = bn

in B. Hence the system has a solution

X• 1 — ru 17 • • • 7 X* n — *~Un

in A. Now, we can define the map q : b1 ^ u17^^bn ^ un. Since (u17^^un) satisfies the defining relations of B, so this map is a lattice homomorphism. Furthermore, we have q(ai) = q(yi(b17 • • ^7 bn)) = ¥i(q(b1)7 • • ^ q(bn)) = ¥i(u17 • • • 7Un) = ai. This shows that q is a retraction. Statement (3) is similar to (2). □

We say that a lattice extension A < B is discriminating, if for any finite set W of elements from B, there exists a retraction h : B ^ A whose restriction into W is injective. The following theorem gives some equivalences of being existentially closed in a lattice B. It is a lattice form of a similar theorem from [3] and so we don't give any proof.

Theorem 2.3. Let A ^ B be a lattice extension. Then the following hold:

(1) If A ^ B is discriminating, then the sublattice A is existentially closed in B.

(2) Suppose that B is finitely generated relative to A and A is equationally noetherian. Then A is existentially closed in B if and only if the extension A ^ B is discriminating.

3. Existentially closed lattices in class of distributive lattices

In [4] J.Schmid studied algebraically closed and existentially closed distributive lattices. He proved that a distributive lattice is algebraically closed if and only if it is a boolean lattice. He showed also that a distributive lattice is existentially closed if and only if it is free of atoms. He worked within the class D whose elements are distributive lattices. In [4] J. Schmid shows that any strongly algebraically closed distributive lattice is a complete boolean lattice. The main aim of this article is to prove that a complete boolean lattice having the property of being q'-compactness is strongly algebraically closed.

Definition 3.1. A lattice A in a class X is said strongly algebraically closed if every system (not necessarily finite) of equations with parameters in A which has a solution in some extension B £ X, has already a solution in A.

We will need the compactness theorem of Godel-Malcev and so we give a short review of this theorem. Recall that a set of formulas T in a language L is called satisfiable in a class X (or T is realized in X), if one can assign some elements from a particular algebraic structure from X as values to the variables which occur in T in such a way that all formulas from T become true. The set T is called finitely satisfiable in X, if every finite subset of T is realized in X (see [1] and [2]).

Theorem 3.2 (Compactness Theorem). If a set of first-order formulas T is finitely satisfiable in a class X, then T has a solution in an ultraproduct of structures from X.

As an special case, we focus on the case of lattices and systems of equations. Let X be a class of lattices, and S be system of equations of lattices. If every finite subset S0 C S has a solution in element of X, then S has a solution in an ultraproduct of elements of X.

Corollary 3.3. Let A be a lattice and S be an arbitrary system of equations over A. If any finite subsystem S has a solution in A, then S has a solution in an ultrapower of A.

Equationally and weak equationally noetherian boolean algebras (with coefficients) are characterized by Shevlyakov in [6]. In the proof of our main theorem, we will need his results. As is shown in [6], a boolean algebra A is equationally noetherian if and only if it is finite; and it is weak equationally noetherian if and only if it is complete. In what follows, we need a new generalization of the concept of equational noetherian algebra. I am grateful to my supervisor M. Shahryari who introduced this idea to me. Let X be a possibly infinite set of variables. Let A be an algebra in a language L. A system S of equations in language L(A) and variables in X is said to be finitary, if it contains finite number of variables. Let S and S' be two finitary systems and suppose that the sets of variables occurring in S and S' are respevtively {x1,..., xn} and {x1,..., xm}. Let also n < m. We say that S is reducible to S' over A, if and only if, for some extension B D A we have VA(S) = An n n(VB(S')). Here n is the projection Bm ^ Bn and VA(S) and VB(S') are the sets of solutions of S and S' in A and B, respectively.

We say that the algebra A is finitary equational noetherian, if every finitary system of equations in the language L(A) is reducible over A to a finite system. The following proposition gives a close connection between completeness of lattices and finiteness conditions for systems of equations.

Proposition 3.4. Let A be an equationally noetherian lattice. Then A is complete. Conversely, if a distributive lattice A is complete, then it is finitary equational noetherian.

Proof. Let A be equational noetherian and K C A be a non-empty set. We show that K has the largest lower bound. Let L = {b e A : b < K} and consider the following system of equations

x A a & x (a e K), x A b & b (b e L).

This system is equivalent over A to some finite subsystem

x A a1 & x,

x

a,n ^^ ^c, x A b1 & b1,

'A bm

b

m

where ai G K and bj G L, for all i and j. Suppose x = ax A ■■■ A an. Clearly, this x is a solution of the second system in A and hence it is a solution of the first system. This shows that /\K = ax A ■ ■ ■ A an, so A is complete.

Now, suppose that A is a complete distributive lattice. As we saw at the end of the Section 2, A can be embedded in a boolean lattice, so suppose that B is the smallest boolean lattice containing A. Clearly B is complete and so, by [6], B is weak equational noetherian in the language L'(B), where L is the language of boolean algebras. Note that every system of equations in the larger language L'(B) can be transformed to a system of equations in L(A), by introducing finitely many new variables and finitely many new equations. Let X be a possibly infinite set of variables and S be a finitary system of equations in the language L(A) and variables xx,... ,xn. We know that there exists a finite system S0 in the language L'(B) (and with the same variables) such that VB(S) = VB(So). Introducing some new variables and new equations in the language L(A), we obtain a finite system T such that VB(S0) = n(VB(T)), where n is a projection. Now, we have

Va(S) = An П Vb (S) = An П Vb (So) = An П n(VB (T)). This shows that S is reducible to a finite system and so A is finitary equational noetherian. □

Let S be a system of equations in A. The set of all logical consequences of S over A is the radical RadA(S). In other words, RadA(S) is the set of all lattice equations f « g such that VA(S) С VA(f « g). We say that two lattices A and B are geometrically equivalent, if for any system S, we have RadA (S) = RadB (S). We say that a lattice A is ^'-compact, if it is geometrically equivalent to any of its elementary extensions. We are now ready to prove our main theorem.

Theorem 3.5. Let A be complete boolean lattice which is q'-compact. Then A is strongly algebraically closed in the class of distributive lattices.

Proof. Let L be the language of boolean algebras. Note that, in the same time we can consider A as a boolean algebra. Let S be a consistent system in the language L(A). Clearly, S is also a system in L'(A). Since A is complete so by [6], it is a weak equational noetherian boolean algebra. So, there is a finite system T in the language L'(A) equivalent to S over A. We know that every finite S0 С S is consistent, and by the result [4] of Schmid, A is algebraically closed. Hence, every such S0 has a solution in A. By Corollary 3.3, S has a solution in some ultra-power B = A1 /U. Note that B is also a distributive lattice, and since it is an elementary extension of A, and A is q'-compact then

Rad^(S) = RadB (S).

On the other hand, we have

Rad^(S) = Rad^(T).

Since T is finite, we also have

Rad&(T) = RadB (T).

This shows that S and T are equivalent over B. Therefore, T has a solution in B and consequently in A. Thus S has a solution in A. Note that according to Proposition 3.4, T is a finite system in the language L'(A). But by introducing a finite number of new variables and a finite number of new equations we can transform it to a finite system in L(A). To do this, we perform the following actions:

1. If T contains the boolean constants 0 and 1, then there will be no change, since 0,1 G A.

2. If T contains therm x', then we introduce a new variable y and insert new equations x A y « 0 and x V y « 1, instead.

3. If there appears a term of the form a', then again there will not be any change. □

References

[1] V.A.Gorbunov, Algebraic theory of quasivarieties, Plenum, New York, 1998.

[2] A.I.Malcev, Algebraic systems, Springer-Verlag, 1973.

[3] A.Miasnikov, V.Rmankov, Verbally closed subgroups of free groups, Journal of Group Theory, 17(2014), 29-40.

[4] J.Schmid, Algebraically and existentially closed distributive lattices, Zeilschr. Math. Logik u. G. M., 25(1979), 525-530.

[5] M.Shahryari, Existentially closed structures and some embedding theorems, Preprint (arXiv:1311.2476).

[6] A.Shevlyakov, Algebraic geometry over boolean algebras in the language with constants, J. Math. Sciences, 20(2015), 724-757.

О сильно алгебраически замкнутых решетках

iНе можете найти то, что вам нужно? Попробуйте сервис подбора литературы.

Али Молхаси

Факультет математических наук Университет Табриза Табриз Иран

В этой статье исследованы некоторые фундаментальные свойства экзистенциально и алгебраически замкнутых решеток. Определено также понятие сильно алгебраически замкнутой решетки. Показано, что q' -компактное полная булева решетка сильно алгебраически замкнута.

Ключевые слова: экзистенциально и алгебраически замкнутые решетки, сильно алгебраически замкнутые решетки, эквационально нетерова решетка, полные булевы алгебры.

i Надоели баннеры? Вы всегда можете отключить рекламу.