ISSN 2074-1871 Уфимский математический журнал. Том 9. № 4 (2017). С. 137-146.
УДК 517.576
MINIMUM MODULUS OF LACUNARY POWER SERIES AND ^-MEASURE OF EXCEPTIONAL SETS
T.M. SALO, O.B. SKASKIV
Abstract. We consider some generalizations of Fenton theorem for the entire functions represented by lacunarv power series. Let f (z) = +=o Лz""fc> where (nk) is a strictly increasing sequence of non-negative integers. We denote by
Mf (r) = max{|/(z)|: |z| = r},
mf (r) = min{|/(z)|: |z| = r},
цf (r) = max{| Д : к ^ 0}
the maximum modulus, the minimum modulus and the maximum term of f, respectively. Let h(r) be a positive continuous function increasing to infinity on [1, with a non-decreasing derivative. For a measurable set E С [1, we introduce h — meas (E) = JE . In this paper we establish conditions guaranteeing that the relations
Mf (r) = (1 + o(1))m/(r), Mf (r) = (1 + o(1))^/(r)
are true as г ^ outside some exceptional set E such that h — meas (E) < For some subclasses we obtain necessary and sufficient conditions. We also provide similar results for entire Dirichlet series.
Keywords: lacunarv power series, minimum modulus, maximum modulus, maximal term, entire Dirichlet series, exceptional set, h-measure
Mathematics Subject Classification: 30B50
1. Introduction
Let L be the class of positive continuous functions increasing to infinity on [0; By L+ we denote the subclass of L consisting of the diiferentiable functions with a non-decreasing derivative, and L~ stands for the subclass of functions with a non-increasing derivative. Let f be an entire function of the form
f (z) = £ fkzn* , (1)
k=0
where (nk) is a strictly increasing of nonnegative integers. Given r > 0, we denote by
Mf (r) = max{|/(z)|: |z| = r}, mf (r) = min{|/(z)|: |z| = r}, ^f (r) = max{|/fc|rrafc: к ^ 0} the maximum modulus, the minimum modulus and the maximum term of f, respectively. P.C. Fenton [1] (see also [2]) proved the following statement.
Theorem 1 ([1]). If
< (2)
Е-
= пм - m
t.m. salo, o.b. skaskiv,the minimum modulus of lacunary power series and h-measure of exceptional sets.
© Salo T.M., Skaskiv O.B. 2017. Поступила 22 июля 2016 г.
then for every entire function f of the form (!) there exists a set E C [1, of finite
logarithmic measure, i.e. log-meas E := fE dlogr < such, that the relations
Mf (r) = (1 + o(1))m/ (r), Mf (r) = (1 + o(1))^ (r) (3)
hold as r ^ (r E E).
P. Erdos and A.J, Maeintvre [2] proved that condition (2) implies that (3) holds as r = rj ^ for some sequenee (rj),
Denote by D(A) the class of entire (absolutely convergent in the complex plane) Diriehlet series of the form
F(z) = ^ anezX", (4)
n=0
where A = (A^) is a fixed sequence such that 0 = A0 < \n t (1 ^ n t +rc>). Let us introduce some notations. Given F E x E R, we denote by
y,(x, F) = max{|ara|e^An : n ^ 0}
the maximal term of series (4), by
M(x, F) = sup{|F(x + iy)l: y E R}
we denote the maximum modulus of series (4), by
m(x, F) = inf{IF(x + iy)l: y E R}
we denote the minimum modulus of series (4), and
v(x, F) = max{n: |an|exA" = y(x, F)}
stands for the central index of series (4),
In [3] (see also [4]) we find the following theorem.
Theorem 2 ([3]). For every entire function F E D(A) the relation
F (x + iy) = (1 + o(1))a„ (5)
holds as x ^ outside some set E of finite Lebesgue mea sure (JE dx < uniformly in y eR, if and only if
1
^ A-T < (6)
1 — A
ra=0
Note, that in the paper [5] there were proved the analogues of other statements in the paper by P.C, Fenton [1] for subclasses of functions F E D(A) defined by various restrictions on the growth rate of the maximal term ^(x,F),
The finiteness of Lebesgue measure of an exceptional set E in theorem A is the best possible description. This is implied by the next statement.
Theorem 3 ([6]). For every sequence A = (Xk) (including those which satisfy (6)J and for every continuously differentiable function h: [0, ^ (0, such that h'(x) ^ (x ^ +<x>) there exist an entire Dirichlet series F E D(\), a constant [3 > 0 and a measurable
set E1 C [0, +<x>) of infinite h-measu,re (h — meas (E1) = dh(x) = such that
(V xeE 1): M (x,F ) > (1 + ¡3)^(x,F), M (x,F) > (1 + ¡3 )m(x,F). (7)
Recently, Ya.V, Mykvtvuk remarked that in Theorem 3, it is sufficient to assume that a
h
h(x)
—> as x —> +oo.
It follows from Theorem 3 that the finiteness of logarithmic measure of an exceptional set E in Fenton's Theorem 1 is also the best possible description.
It is easy to see that the relation
F (x + iy) = (1 + o(1)K (x,F)e(x+iy)x"^F) holds as x ^ (x e E) uniformly in y e R if and only if
M(x,F) ~ ^(x,F) and M(x,F) ~ m(x,F) (x ^ x / E). (8)
In view of Theorem 3, the natural question arises: what conditions should an entire Dirichlet series satisfy in order to relation (5) be true as x ^ outside some set E2 ofhnite h-measure, i.e.,
h — meas (E2) < In this paper we provide the answer to this question as h e L+.
h—
According to Theorem 3, in the case h e L+, condition (6) must be fulfilled. Therefore, in the subclass
D(A, $) = {F e D(A) : lnF) ^ x$(x) (x>Xo)}, $ e L, it should be strengthened. The following theorem indicates this.
Theorem 4. Let $ e L,h e L+ and ip be the inverse function for the function $. If
+ ^0
(V6> 0): £ . 1 . tiL(\k)+ . b ,)< +«>, (9)
— Ah+1 — Ah V Ah+1 — Ak'
k=0
Afc+i — Xk \ Afc+i — Xk
then for all F e D(A, $) identity (5) is true as x ^ outside some set E of a finite h-measure uniformly in y e R.
Before proving this theorem, we need additional notations and an auxiliary lemma. Denote A0 = 0 and
n-1 rc , 1 1 x
A = — A,) £ [x _x + --— .
=0 _ +i ^m— 1 Am+1 ^m J
for n ^ 1, The next lemma is similar to Lemma 1 in [8], Lemma 1. For all n ^ 0 and k ^ 1, the inequality
is true, where an = eqAn, q > 0, and
, v . Q Ak-1 — aa Tk = rk (q) = qxk + T-7-, xk
Xk — Xk-1 Xk — Xk-1
Proof. Since
ln an — ln an-1 = q(An — An-1) = —qxn(Xn — Xn-1),
for n ^ k + 1 we have
ln — + Tk(\n - \k) = - q x3(X3 - X3-i) + rk (Xj - Xj-i )
ak j=k+i j=k+i
n
= - Y1 (qxi - Tk) (X3 - Xi-i) j=k+i n
j=k+i n
Q 1 = -q(n - k)-j=k+i
Similarly, for n ^ k - 1 we obtain
ln — + rk(\n - \k) = - ln — - rk(\k - Xn)
ak an
k
--Q
Y^ Xi (Xi - X3-i) - Tk Y (Xi - X3-i)
j=n+i
j=n+i k
= - Y1(rk - qxi) (xi- Xi-i)
j=n+i k
^ - Y (ri - qxi)(Xi - Xi-i)
j=n+i
k
qY 1 = -Q(k -
j=n+i
and this completes the proof.
□
a
an
n ezXn.
Proof of Theorem 4- We first note that condition (9) implies the convergence of series (6). We consider the function
f* (*) = £■
n=0
Since An ^ 0, we have fq G D(A) and v(x, fq) ^ (x ^ +œ).
Let J be the range of the central index v(x,fq). Denote by (Rk) the sequence of the jump points of central index, numbered in such a way that v(x,fq) = k for all x G [Rk, Rk+i) and Rk < Rk+i. Then for all x G [Rk, Rk+i) and n ^ 0 we have
a
—exXn e
According to Lemma 1, for x G [Rk + rk, Rk+i + rk) we obtain
anexXn . a.
ak
x\k
akexX* ak
^ ^ erk(An-Afc) ^ g-^^ (n ^ o).
Therefore, and
v(x,F) = k, ß(x,F) = akexXk (x G [Rk + rk,Rk+i + rk)) IF(x + iy) - av{XtF)e(x+w)K(*>F) | ^ ^ ß(x, F)e-^-^>F)|
n=v(x,F )
,-q
(11)
C2
1 - e—
ß(x,F)
for all x e [Rk + Tk, Rk+1 + rt^d k e J. Thus, inequality (12) holds for all
def +°°
x e E1(q) = U [Rk+1 + Tk, Rk+1 + Tk+1). k=0
Since
2q
Tk+1 — Tk = T-7-,
Ak+1 — Ak
and by the Lagrange theorem
h( Rk+1 + Tk+1) — h( Rk+1 + Tk) = (Tk+1 — Tk )h'( Rk+1 + Tk + ^ (rk+1 — Tk)), where 6k e (0; 1), for each q > 0 we have
rRk+1+ rk+i
h — meas (E1(q)) = ^^ j dh(x)
k=0 k+i +Tk +<x
= ^(h( Rk+1 + Tk+1) — h( Rk+1 + Tk)) (13)
k=0
+<x
^2q V --tíÍRk+i + Tk + 2g--).
— Ak+1 — Ak V Ak+1 — Ak '
k=0
Here we have employed the condition h e L+. For F e D(A, x > max{x0,1} we have
X
x$(x) ^ \n^(x,F) = ln^(1,F) + J )dx ^ ln^(1,F) + (x — 1)Xu(x-0,f).
1
This implies
X$(X) ^ X\v(x-0,F) (14)
for all x ^ x1 ^ x0, i.e.
X (Xu(X-0,F)) (X ^ X1).
Thus, according to (11), for k ^ k0 we obtain
Rk+1 + Tk ^ (Xv(Rk+1+Tk-0,F)) = ). Applying this inequality to inequality (13), by the condition h e L+ we have
1 1
h — meas(E1(q)) ^ 2 q V---h' L(Xk) + 2q---V (15)
Ak+1 — Ak V Ak+1 — Ak^
Therefore, using (9) we conclude that h — meas ( E1(q)) < Let qk = k. Since h — meas (E1(qk)) < we have
h — meas (E1(qk) H [x, = o(1) (x ^
hence, it is possible to choose an increasing to sequence (xk) such that
h — meas (£1(qk) H [xk; +rc>)) ^ jt.
k2
+00
for all k ^ 1. Denote E1 = (J {E1(qk) H [xk;xk+1)). Then
k=1
+0 +0 1
h - meas (Ei) = ^ h - meas (Ei(qk) H [xk; Xk+1)) ^ ^ ~¡2 < k=1 k=1
On the other hand, by inequality (12), for x G [xk; xu+i) \ El we get
\F(x + iy) — av(x>F| ^ 2 ---»(x, F),
1 — e qk
and therefore, as x ^ (x G El), we obtain (5), The proof is complete, □
We observe that if h(x) = x, then condition (9) becomes condition (6), and h-measure of the set E is its Lebesgue measure. Let $ G L. Consider the classes
Do(A, $) = {F G D(A) : (3K > 0)[ln¡i(x, $) ^ Kx$(x) (x > a^)]}, Di(A, $) = {F G D(A) : (3Ki,K2 > 0)[ln¡i(x, $) ^ Kix$(K2x) (x > a*)]}.
Theorem 5. Let $0 G L, h G L+ and tp0 be the inverse function for the function $0. If
1 / h \
(Vb > 0) : V ---h' MbK) + t-r < (16)
^=0 ^n+l — An \ An+i — AnJ
then for each function F G D0(A, $0) relation (5) holds as x ^ outside some set E of finite h - measure uniformly in y G R.
Theorem 6. Let $l G L, h G L+, and <pl be the inverse function to the function If
+ ^0
> 0)^ h'(b^i(b\„,)) < (17) „ An+i — An
n=0
then for every function F G Dl(A, $l) relation (5) holds as x ^ outside some set E of finite h-measure uniformly in y G R.
Proof of Theorems 5 and 6. Theorems 5 and 6 are implied immediately by Theorem 4,
Indeed, if F G D0(A, $0), then F G D(A, $) as $(x) = K$0(x). But in this case ip(x) = <p0(x/K) and condition (9) follows condition (16), Then it remains to apply Theorem 4.
In the same way, if F G Dl(A, then F G D(A, $) as $(x) = Kl$l(K2x). But in this case ip(x) = tpl(x/Kl)/K2 and hence, condition (9) follows condition (17), It remains to employ Theorem 4 once again, □
Remark 1. It is easy to see that for each, fixed functions h G L+ and $ G L there exists a A
The next theorem shows that condition (17) is necessary for relations (5), (8) to hold for each F G Dl(A, $l) as x ^ outside a set of a finite h-measure. Here we assume that condition (6) is satisfied.
Theorem 7. Let $l G L, h G L+, and tpl be the inverse function for the function For A
{3b > 0): g h'(PMb\n)) = (lg)
„ An+i — \n
n=0
there exist a function F G Dl(A, a set E C [0, and a constant ft > 0 such, that inequalities (7) hold for all x G E and h — meas (E) =
n-2
Proof. We denote k1 = k2 = 1, nn = rk, (n * 3), where
k=1
ri = max Ibtpi(bX2), ^ ^ ^
rk = ma^ibpi(bXk+i) - bpi(bXk), --1—— ) ( k ^ 2),
^ Xk+i — Xk J
u+1 — Ak and we also choose
n
00 = 1, an = exp j — ^ Kk(Xk — Xk-1)} (n * 1).
k=1
We prove that the function F defined by series (4) with the above defined coefficients (an) and the exponents ( Ara) belongs to the class ^1(A, $1). Since the condition
EX - X <
n Xn+1 — Xn n=0
ln n
implies n2 = o(Xn) (n ^ we have —--> 0 (n ^ By the construction,
Xn
ln an-1 — ln an Kn = -^^T- (n * 1)
ln a
and Kn ^ + w (n ^ Therefore Stolz theorem yields that--^ (n ^ and
Xn
by Valiron formula [9] the abscissa of the absolute convergence of series (4) is equal to i.e., F e D(A).
Moreover, it is known that in the case nn ^ (n ^ we have
Vx e [xn, Kn+1) : ^(x,F) = anexK, v(x,F) = n. (19)
Since by the construction
n-2 1
Kn ^ bifi1(bXn-1) + y] --r- ^ 2bIfi1 (bXn-1) (n > U0),
t~1 Ak+1 — Ak
for sufficiently large n for all x e [nn, xn+1) we have
2x
lny(2x, F) = ln y(x, F) + / Xv(t)dt * xXu(x)
* * 1 $>(Kf) * I$1 (!)-
Hence, for x * x0 we have
1 / x \ \nß(x,F) £ -x*i{Tb)
and thus F e Di(A, $i). We observe that
1
Kn+i - Kn = T'n-i ^ X _ X- (n ^ 1).
X n - Xn i
For x G
Kni Kn + i
^n—^n. — 1
we have
a i gx1 et i Gx1
-^7-= n- x\-= exp{(Xn - Xn-i)(Kn - x)} ^ := ß, (20)
ß(x,F ) anexÄn
n=1
and, therefore, for x G E = (J xn, xn + — , by choosing n = u(x, F) we get
( a 11 \
F(x) ^ an-iexXn-1 + anexX" = ^(x, F) 1 + n-1 xX ^ (1 + ft)fi(x, F).
v anexA" y
Hence, inequalities (7) are true.
Now we prove that h — meas (E) = By the construction of (xra) for all n ^ 1 we have
K. ^ btpi(b\n-i). (21)
Taking into consideration the Lagrange theorem, the condition h G L+ and inequality (21), we obtain
1
„ , 1 X
h — meas (E) = V^ dh(x) = I h(xra + ----) — h(xn) )
t=1 J t=1\ Xn — Xn-1 /
ra=1 ra=1
Xn
> h'(xra) > h'(6^i(6Ara-i)) _ +
>^A-A 1 > ^ ^ - A 1 _
n=1 n=1
The proof is complete. □
The next criterion is implied immediately by Theorems 6 and 7.
Theorem 8. Let $1 G L, h G L+ and <p1 be the inverse function for the function For each entire function F G D1(A, $1) relation (5) holds as x ^ outside some set E of a finite h-measure uniformly in y G R if and only if (17) is true.
It is worth noting that if condition (16) of Theorem 5 is not fulfilled, that is
i / b \
(3b 1 > 0) : V --- h' Mb A) + T—^ ) _
An+1 — An V An+1 — An y
then for b _ max{61; 2} we have
h'(bipo(bAn))
> —:-7— _
An+1 — An
n=0
Therefore, condition (18) holds and according Theorem 7, there exist a function F G D1(A, $0) a set E c [0, +rc>) and a constant ft > 0 such that inequalities (7) hold for all x G E and
h — meas (E) _
Since for $0(x) _ xa, a > 0, we have D0(A, $0) _ D1(A, $0), from Theorem 5 and 7 we obtain the following theorem.
Theorem 9. Let $0(x) _ xa (a > 0), h G L+. For each entire function F G D0(A, $0) relation (5) holds as x ^ outside some set E of a finite h-measure uniformly in y G R if and only if
i / h \ (Vb > 0) : £ A--h' b(An)1/a + A ° A <
n=0 An+1 — An \ An+1 — An y
is true.
3. ^-measure with a non-increasing density
We note that for each differentiable function h : R+ ^ R+ with a bounded derivative h'(x) ^ c < (x > 0) we have
/ dh(x) = h'(x)dx ^ c / dx.
JE JE <JE
Hence, the finiteness of Lebesgue measure of a set E c R+ implies h — meas (E) < Therefore, according Theorem A, condition (6) provides that the exceptional set E is of a finite h-measure. However, we conjecture that for h E L- in the subclass
DV(A) = {F E D(A) : (3no)(Vn > n,)[M ^ exp{ —Aray(Ara)}]}, y E L,
condition (6) can be weakened significantly. The following conjecture seems to be true.
Conjecture 1. Let y E L, h E L-. If
h'(p(X,n))
n=0 Xn+i - Xn
< +oo,
then for all F e DV(A) relation (5) is true as x ^ outside some set E of finite h-measu,re uniformly in ye R.
h—
The important corollaries for entire functions represented by a laeunarv power series of the form (1) are implied by the proven theorems.
For an entire function f of the form (1) we let F(z) = f(ez), z e C, We observe that as x = lnr, y = <p,
F (x + iy) = F (lnr + iip) = f(r eiip)
and M(x,F) = Mf (r), m(x,F) = mf (r), ^(x,F) = ^f(r), u(x,F) = Uf(r), In addition, for
def
E2 = (re R : lnr e E1} and h1 such th at h[(x) = h'(ex) we have
def f dh(r) f dh(ex) f h — log — meas(E2) = -= --— = dh1(x) = h1 — meas(E1).
Je2 r JE i eX J Ei
The next corollary is implied by Theorem B,
Corollary 1. For each sequence (nk) such, that condition (6) holds and for each function h e L+ there exist an entire function f of the form (1), a constant [3 > 0 and a set E2 of an infinite h-log-measure, i.e.( §E = such that
(Vr e E2) : Mf (r) * (1+[)/if (r), Mf (r) * (1+[)mf (r). (22)
By Theorem 4 we obtain the following corollary.
Corollary 2. Let $ e L, h e L+ and p be the inverse function for the function $. If for an
ln^f(r) * lnr$(lnr) (r * r0) (23)
and
(Vb > 0): V-h'( exp{p(nk) +-}) < (24)
nk+1 — nk V I nk+1 — nk)J
then the relation
f(r eiip) = (1 + 0(1))^ {r)rnvfw ewnvf w (25)
holds as r ^ outside some set E2 of finite h-log-measure uniformly in p e [0, 2ir}.
In fact, it follows from condition (23) that F G D(A, $) with A _ (nk) and it remains to
h1
Denote by E the class of entire functions of positive lower order, i.e.
Af :_ lim lnlnMf (r)/lnr > 0.
T—^ +
By Theorem 8 we obtain the following corollary.
Corollary 3. Let h G L+. In order the relations (3) hold for each function f G E of the form (1) as r ^ outside a set of a finite h-log-measure, it is necessary and sufficient to have
(Vb > 0) : V-h'((nk)b) <
t=0 nk+1 — nk
Acknowledgements
We are grateful to Prof, I.E. Chyzhvkov and Dr. A.O. Kurvliak for helpful comments and corrections in the previous versions of this paper.
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Tetyana Mykhailivna Salo,
Institute of Applied Mathematics and Fundamental Sciences,
National University "Lvivs'ka Polytehnika",
Stepan Bandera str. 12,
79013, Lviv, Ukraine
E-mail: [email protected]
Oleh Bohdanovych Skaskiv,
Department of Mechanics and Mathematics,
Ivan Franko National University of L'viv,
Universytetska str. 1,
79000, Lviv, Ukraine
E-mail: [email protected]