Научная статья на тему 'On the stability of the boundary value problem for even order equation'

On the stability of the boundary value problem for even order equation Текст научной статьи по специальности «Математика»

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Ключевые слова
partial differential equations / ill-posed problem / boundary value problem / algebraic numbers / the simple continued fraction

Аннотация научной статьи по математике, автор научной работы — Yuldasheva Asal Victorovna

In this paper we consider ill-posed problem for one even-order equation. The stability of the problem is proved with the additional assumption.

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Текст научной работы на тему «On the stability of the boundary value problem for even order equation»

Bulletin KRASEC. Phys. & Math. Sci, 2015, V. 10, №. 1, pp. 4-10. ISSN 2313-0156

MATHEMATICS

MSC 47F52+47F05

ON THE STABILITY OF THE BOUNDARY VALUE PROBLEM FOR EVEN ORDER EQUATION

A.V. Yuldasheva

National University of Uzbekistan by Mirzo Ulugbeka, 100174, Uzbekistan, Tashkent c., VUZ gorodok st. E-mail: [email protected]

In this paper we consider ill-posed problem for one even-order equation. The stability of the problem is proved with the additional assumption.

Key words: partial differential equations, ill-posed problem, boundary value problem, algebraic numbers, the simple continued fraction

Introduction

We consider following problem for even order equation:

= 0, k, p e N, 0 < x < n, 0 < t < an,

dx2k dt2P d2mu ,„ , d2mu

(0,t) = —^~ (n,t) = 0, m = 0,1,...,k- 1, 0 < t < an, d x

(x,0) = pj (x), j = 0,1,...,p- 1, 0 < x < n,

dx2m ' d x2m d ju

d tj d j u

—r (x, an) = Yj (x), j = 0,1,...,p- 1, 0 < x < n,

where a is a positive constant.

If k = p = 1 we get The Dirichlet problem for the vibrating string equation, which is a classical ill-posed problem due to its irregular behavior. Its solution may neither exists, nor be uniquely determined, nor depend continuously on the data (see [1]-[3]).

In [2], the Dirichlet problem for the wave equation was studied with the additional assumption of an "a priori" bound for the gradient of the solution. Case when p = 1, k e N was studied in [6].

The present research leads to some problems of Diophantine approximation. Let us note that formulate problem is ill-posed problem if k — p is even number. Therefore, the above problem cannot be suitably dealt with if a and pj (x), Yj (x), j = 0, 1, . . . , p - 1 are known within a certain approximation.

Yuldasheva Asal Victorovna - Ph.D. (Phys. Math.), Lecturer of the Dep. Differential Equations and Mathematical Physics, of the National University of Uzbekistan by M. Ulugbek, Tashkent.

©Yuldasheva A.V., 2015.

Main results and comments

Let çj (x), yj (x), ( j = 0,1,..., p - 1) be functions in C2k [0, n] such that ç )2l> (0) =

,(20

çj2,) (n) = Yj2i)(0) = Yj2,)(n) = 0, , = 0,1,...,k- 1, j = 0,1,...,p - 1 .

Let t, E, a, 5 be positive constants. We consider solutions u in C2/2p ([0, n] x (0, +^]) of the following problem:

r(2f)

d2ku Ä

dx2k dt2P

= 0, k, p G N, 0 < x < n, t > 0,

d 2m w d 2m w

^ (0,t) = ~dX2fn (n,t) = 0, m = 0 l,...,k-l, t > 0,

d ju

d tj

(x, 0) - çj (x)

d ju

d tj

tj k) - Yj (x)

L2[0,n ]

< 5nVE, j = 0,1,...,p- 1,

L2[0,n ]

< önVE, j = 0,1,..., p - 1, I Tj - a | < 5,

dxv +

d pu ~dfP

I dx < E, t > 0.

(1) (2)

(3)

(4)

(5)

for real numbers Tj, j = 0,1,...,p — 1 depending on u and satisfying \xj — a| < 5. The meaning | Tj — a | < 5 is that the final time an is known up to a given error.

We denote by r5 the set of all C^'2p ([0,n] x (0, +~]) solutions of (1-(5). We note that if 5 = 0, then the problem (1-(5) is reduced to the classical boundary value problem with additional assumption (5). It was studied in [6] that this problem may have no solutions.

Let DiamF5 = sup ||v — w||. Let v1, v2 G r5. Then there are Tj such that

v,wer5

d ju

d tj

and let

x, Tjn) - Yj (x)

L2[0,n ]

< 5n VE, i = 0,1, j = 0,1,..., p - 1, | Tij - a |< 5

u (x, t) = v1 (x, t) - v2 (x, t), (x, t) g [0, n] x [0, +<*>)

(6)

Then u g C2xfp ([0, n] x [0, +<^)). Moreover, u satisfies equation (1), conditions (2) and following

d ]U' ~ < 25n VË, j = 0,1,..., p - 1, (7)

L2[0,n ]

d tj

j (x, 0)

d ju

~dtJ

(x, an) - Yj (x)

L2[0,n ]

< 45nVE, j = 0,1,...,p - 1,

d^uY d xk)

+

d pu ~dfP

\dx < 4E, t > 0.

(8) (9)

n

2

It is easy to verify (1), (2), (7)-(9). We can write the function satisfying (1) and (2) in the following form

, , ^ . I An sinnp (an — t) . k u(x,t) = £ sinnx <-k--+ Bnsinnpt }.

n>i I sin up an

Similarly, we can rewrite (7)-(9) as follows:

£ An < 852nE,

ni

£ BnsinV an < 3252E,

ni

d ku

d xk

(•, t )

+

L2 [0,n]

d pu

d tp

(•, t )

La[0,x ]

< 4E, t > 0.

(10) (11)

(12)

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Defining:

we obtain from (12)

On = \ —

n ( An sin up (an — t)

+ Bn sin npt

sinnp an

dkuf x 2 (•, t )

d xk

< £ n2kOn2 < 4E,

L2[0,n ] n>1

whence

N

N

I u 0, t )\\2Li [0,n] = £ On2 + £ On2 < £ On2 + 4E

n=1 n=N+1

n=1

N 2k'

We now have following bound:

2 n l k n —2 N

\u (•, t )\\^ [0,n] < n max (sin up an

n=1N

£

n=1

AUsin2up (an — t) + BUsin2up an • sin2up t +

sin npt

sinup an

+2 |An||Bn| sinnp (an -1) Therefore, from (10) and (11) it follows that

+ 4E

+ N2k .

max 1 \\u (•, t)\L2[0,n] = \\u\\2 < 4052n2E ma

E[0,an] /L ' J n=1

t e[0,an ]

max I sinup an

,N

2 4E

+ NEk,N =1,2,....

Let

a=

1

a1 +

1

Û2 + ...

be the simple continued fraction for a, where the partial quotients an are integers such that, an > 1.

We consider the set of irrational numbers with bounded partial quotients, i.e. the numbers a, for which there exists a constant Aa satisfying an < Aa for all n . We note that if a is a quadratic irrational, then the expansion of a as a simple continued fraction is ultimately periodic, which implies that an has bounded partial quotients.

2

2

Then from theory of continued fractions (see [5] p.37) we easily obtain

max

n

ax fsin up an) <

1 ,N V )

-2

n

sin

(Aa + 2) Nr

, N = 1,2,

Since sinx > ^n3x for x e [0,%/3], we have for every N

2k

-8 2 n 2E (Aa + 2)2N

27

(13)

u\\2 < 52 n 2E (Aa + 2)2N p + , N = 1,2,...

N2k

Now let

2k

g (t) = 127052n2E(Aa + 2)2t P + 4Et

The minimum value of g for t > 0 is attained at

p

p

t =( ^ 2k ( p + 1)(Sn (Aa + 2))-k (p + 1)

Since g is an increasing function on the interval [t, we have

g([t + 1]) < g(t + 1).

We obtain

. Il2 160E/C ^..Jp.

|u\\2 <— (5n (Aa + 2)) p+1

1 +

27p\ (p+1)2k

p ■

(p+1)k

+ (5n (Aa + 2))

2k p

(14)

So we proved following

Theorem 1. Let a is an irrational number and has the simple continued fraction with bounded partial quotients. Then for (Diamr$) (14) is valid.

Now we use some results obtained in [4]. By corollary 6 of [7], since a has a type Q < there exist K = K (Q, a) > 0 and, for any 8 > 0, a number % e R\Q such that

li — a| < 5,

and

max (sin uni ) < I sin

n=1,N 1

n (3 — V5

-2

2N

(15)

(16)

for all N > K8 Q. From (15) it follows that \xj — a| < 8, for every Tj satisfying — Tj| < 28.

If u is defined by (6), we obtain from (8) d ju

d tj

(x, )

< 45^V/E, j = 0,1,...,p - 1. (17)

L2[0,n ]

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Therefore, u satisfies conditions (1), (2), (7), (9) and (17). The solutions of the problem (1), (2), (7), (9) and (17) u g C2xk,2p ([0, n] x [0, +<*>)) of the form

, , ^ . [ An sinw (Bn -1) . k

u(x,t) = £ sinnx <-k--+ Bnsinnpt

n>1 [ sinnp Bn

which satisfies (10), (12) and

£ Bnsin2npBn < 7252E. (18)

n>1

As in proof of theorem 1 we obtain

o / k \ -2 4E

lluM2 < 805 2n 2E max sin np Bn + , N = 1,2,....

n=1,NV / N2k

Using (16) and sinx > |x for all x g [0, f], we obtain

o 80 i i 2k 4E a

llull2 <-52n2EN2k + 4Ekr, N > K5-e. (19)

(3 -V5)2 N

Let

2k

g(t) = , 8V,2 52n2Et p + 42k, t > 0. (20)

(3 -v^)2 t

The minimum of g for t > 0 is attained at

^ —p

/3-A/5\ k0

t = ( p ) 2k( p + 1)f 3-V^ k(p + 1)

207 \ K5 J

We choose 5 as

k(p +1)

P / ^ \^TT] k0 (P + 1) - P 0 < 5 « k(|) 2k(p + ^ k(p + 1)[ . (21)

It follows from (21) that t < K5—e. Let N be the integer > K5—e for which the right side of (20) is minimum. Since g is increasing on the interval [t, , N satisfies K5—e < N < K5—e + 1. Hence

||u||2 < g (K5—e + A ,

and finally

, „о 80n2E

u2 <

(3 -v^)

■ k K 8 P-в + 8 p

2k

P 4E 8 2ke + —kvt

(22)

which proofs following:

Theorem 2. Let a be an irrational number and has a type Q < ^ Then for any

fixed в,

a

a +1

< в < 1, there is constant K = K(в, a) > 0 such that

, ll2 80n2E

u2 <

(3 -v^)

p

kk

—-в —

K 8 P + 8 P

2k

P 4E 8 2ke

+

for any 0 < 8 < < K (20) 2k(P + 1) ( k(p + 1)

k( P +1)

I_) ke (p + 1) - P

We conclude with the proof of the following: Theorem 3. The problem (1)-(5) is stable if and only if a is irrational. Moreover,

if a is irrational then lim (DiamFs) = 0 uniformly in pj (x), Yj (x), (j = 0,1,...,p — 1)

8 ^0

Proof. Let a e Q. By corollary 9 of [4], there exist a function f (8) such that

lim f (8) = lim 8 f (8) = 0,

(23)

and, for any sufficiently small 8, a number % e Q, satisfying (15) and (16) for all N > f (8) . The same argument given in the proof of theorem 2 shows that

N2 < g(f (8) + 1),

where g is defined by (20), i.e.

, ll2 80n2E U 2 <

(3 -V5)2

■ к t f (8 ) 8 p + 8 p

2k P

+

4E

f(8)

2k

By (23), this yields

References

lim (DiamF8 ) = 0.

80

1. Bourgin-R. Duffin. D.G. The Dirichlet problem for the vibrating string equation. Bull. Amer. Math. Soc., 45(1939), 851-858.

2. Fox-C. Pucci. D. The Dirichlet problem for the wave equation. Ann. Mat. Pura Appl. (IV), vol. XLVI (1958),pp. 155-182.

3. John F. The Dirichlet problem for a hyperbolic equation. Amer. J. Math., 63(1941), pp. 141-154.

4. Viola C. Diophantine approximation in short intervals, Ann. Scuola Norm. Sup. Pisa, 6(1979), pp. 703-717.

5. Khinchin A. Ya. Continued fractions. The Universiry of Chicago Press, 1964, 112 p.

6. Yuldasheva А.V. On one problem for high-order. Reports of the Academy of Sciences of Uzbekistan, Tashkent, 2012, №5, pp. 11-14.

Original article submitted: 23.03.2015

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