Научная статья на тему 'ON THE MOTION OF THE CHAPLYGIN SLEIGH ON A HORIZONTAL PLANE WITH DRY FRICTION AT THREE POINTS OF CONTACT'

ON THE MOTION OF THE CHAPLYGIN SLEIGH ON A HORIZONTAL PLANE WITH DRY FRICTION AT THREE POINTS OF CONTACT Текст научной статьи по специальности «Физика»

CC BY
38
13
i Надоели баннеры? Вы всегда можете отключить рекламу.
Журнал
Russian Journal of Nonlinear Dynamics
Scopus
ВАК
RSCI
MathSciNet
zbMATH
Область наук
Ключевые слова
DRY FRICTION / CHAPLYGIN SLEIGH

Аннотация научной статьи по физике, автор научной работы — Shamin Alexander Yu.

This paper addresses the problem of the motion of the Chaplygin sleigh, a rigid body with three legs in contact with a horizontal plane, one of which is equipped with a semicircular skate orthogonal to the horizontal plane. The problem is considered in a nonholonomic setting: assuming that the blade cannot slide in a direction perpendicular to its plane, but unlike the Chaplygin problem, there is a dry friction force in the skate that is directed along the skate, along which the blade plane and the reference plane intersect. It is also assumed that at the two other points of support there are dry friction forces. The equations of motion of the Chaplygin sleigh are obtained, and a number of properties are proved. It is proved that the movement ceases in finite time. The possibility of realizing the nonnegativity of normal reactions is discussed. The case of static friction is studied when the blade velocity is v = 0. A region of stagnation where the system rotates about a fixed vertical axis is found. On this set, the equations of motion are integrated and the law of variation of the angular velocity is found. Examples of trajectories of the sleigh are given. A qualitative description of the motion is obtained: the behavior of the phase curves in a neighborhood of the equilibrium point is investigated depending on the geometric and mass characteristics of the system.

i Надоели баннеры? Вы всегда можете отключить рекламу.
iНе можете найти то, что вам нужно? Попробуйте сервис подбора литературы.
i Надоели баннеры? Вы всегда можете отключить рекламу.

Текст научной работы на тему «ON THE MOTION OF THE CHAPLYGIN SLEIGH ON A HORIZONTAL PLANE WITH DRY FRICTION AT THREE POINTS OF CONTACT»

Russian Journal of Nonlinear Dynamics, 2019, vol. 15, no. 2, pp. 159-169. Full-texts are available at http://nd.ics.org.ru DOI: 10.20537/nd190205

NONLINEAR PHYSICS AND MECHANICS

MSC 2010: 70F25, 70F40

On the Motion of the Chaplygin Sleigh on a Horizontal Plane with Dry Friction at Three Points of Contact

A. Yu. Shamin

This paper addresses the problem of the motion of the Chaplygin sleigh, a rigid body with three legs in contact with a horizontal plane, one of which is equipped with a semicircular skate orthogonal to the horizontal plane. The problem is considered in a nonholonomic setting: assuming that the blade cannot slide in a direction perpendicular to its plane, but unlike the Chaplygin problem, there is a dry friction force in the skate that is directed along the skate, along which the blade plane and the reference plane intersect. It is also assumed that at the two other points of support there are dry friction forces.

The equations of motion of the Chaplygin sleigh are obtained, and a number of properties are proved. It is proved that the movement ceases in finite time. The possibility of realizing the nonnegativity of normal reactions is discussed. The case of static friction is studied when the blade velocity is v = 0. A region of stagnation where the system rotates about a fixed vertical axis is found. On this set, the equations of motion are integrated and the law of variation of the angular velocity is found. Examples of trajectories of the sleigh are given. A qualitative description of the motion is obtained: the behavior of the phase curves in a neighborhood of the equilibrium point is investigated depending on the geometric and mass characteristics of the system.

Keywords: dry friction, Chaplygin sleigh

Received February 25, 2019 Accepted April 23, 2019

This work was supported by the Russian Foundation for Basic Research (19-01-00140).

Alexander Yu. Shamin shamin_ay@mail.ru

Moscow State University,

Vorobievy gory 1, Moscow, 119899 Russia

1. Introduction

This paper is concerned with the problem of the motion of the Chaplygin sleigh, a rigid body with three legs in contact with a horizontal plane, one of which is equipped with a semicircular knife edge orthogonal to the supporting plane. The problem is considered in a nonholonomic setting, under the assumption that the knife edge cannot slide in the direction perpendicular to its plane, but, in contrast to the Chaplygin problem, the skate has dry friction force, which is directed along the skate, where the plane of the knife edge and the supporting plane intersect. It is also assumed that the body is acted upon by dry friction forces at two other supporting points as well.

In the absence of friction at the points of contact of the body with the plane the problem under consideration becomes the Chaplygin problem [1, 2], and in the absence of a knife edge and in the presence of friction at all points of contact it becomes the problem of the motion of a tripod on a plane with friction [3]. The case where there is no friction at the point of contact of the knife edge with the plane is dealt with in [4]. At present, problems concerning the mechanics of systems with friction are becoming topics of much current interest. Mention should also be made of Refs. [5-7], which investigate various mechanical systems with dry friction.

In this paper, equations of motion of the system of interest are written out, a qualitative analysis of the body motion is given, and the phase portrait of the system in a neighborhood of an equilibrium point is investigated.

2. Formulation of the problem

Consider a rigid body moving with three points A, B and C in contact with a horizontal plane (see Fig. 1). The body is an isosceles triangle (AC = BC, C being the supporting point of the knife edge). It is assumed that the plane of the knife edge is orthogonal to the supporting plane and intersects with the latter along the symmetry axis EC of the triangle ABC, and the center of mass S of the body is projected into the point D, which lies on this axis (AE = EB = a, ED = b, DC = c,DS = h).

Let Oxyz be a fixed coordinate system (Oxy being the supporting plane and Oz the upward vertical) and let S(n( be the principal central axes of inertia of the body, with S(\\Oz. Let ex,ey,ez and e,t,en,e,Z denote the unit vectors of the axes Oxyz and S(n(, respectively:

e, = ex cos p + ey sin p, ev = —ex sin p + ey cos p, e,, = ez,

where p is the angle between the axes Ox and S£.

Assume that the velocity of the point C of the body is vc = ve, (the body cannot slide in the direction orthogonal to the plane of the knife edge), and the angular velocity of the body is co = ue, (w = tp), that is, the body can rotate only about the vertical passing through point C.

If the body moves without loss of contact with the plane, the velocity vS of its center of mass and the velocities va,vb of its supporting points A,B are defined by

vS = vC + [w, CS] = ve, — wcev, Va = vC + [w, CA] = (v + aw)e, — (b + c)wev, vB = vc + [w, cB] = (v — aw)e, — (b + c)wev.

Fig. 1. The Chaplygin sleigh.

The body is acted upon by the gravity force P = -mge^ (m is the mass of the body and g is the free-fall acceleration), which is applied at point S, and by the reaction forces Ra, Rb, Rc applied at points A,B,C:

Ra = Naec - kNA — , RB = Nbec - kNB — , Rc = Ncec + Ffy(v)e< + Re„, VA Vb

G [-kcNc; kcNc], V = 0.

Here Na,Nb,Nc are the normal reactions at the points of support, k > 0 is the coefficient of Coulomb friction at the points A, B of contact of the legs of the sleigh with the plane, kc > 0 is the coefficient of Coulomb friction for the knife edge at point C (in the general case k = kc), and R is the reaction of the nonholonomic constraint (vc ,en) = 0, va =

= sj(v + au)'2 + (b + c)2lo2, vb = -\f {v — ouj)2 + (b + c)2w2, vc = M-

2.1. Definition of reactions

The principal vector of forces that acts on the body has the form F = F^ëç + Fvev + F^e^,

fNA^NB\ (NB Na\

Ft = -k--1--v + FiY(v) + k---aw,

V VA VB J \VB VA J

Fv = k(^ + (b + c)u + R,

' V VA VB J Fc = Na + Nb + Nc - mg.

Let us find the principal vector of the torques acting on the body relative to its center of mass

M = —A, Ra] + -~B, RB] + [—C, Rc] = + Mvev + MZeZ,

M* = a(NB - Na) + kh (— + — ) (b + c)w + hR, 5 \VA Vb )

M„ = b(NA + NB) - cNc + kh (— + — ) v - Fir(v)h - kh (— - — ) auj, 1 \VA VB J \VB Va )

(NB Na\ i(na.Nb\ii2 . p

Mr = k---av — k--1--(r — c(b + c))oj + cR,

Z \Vb Va ) \ Va Vb J

where l2 = a2 + (b + c)2. Thus, projected onto the principal central axes of inertia of the body, the equations of motion of the body in the Newton-Euler form which take into account the conditions of motion without loss of contact of the body with the plane ((vS, e,) = 0, (w, e,) = = (w, en) = 0) have the form (J is the moment of inertia of the body relative to the axis

SO

m(V + cw2) = F,, m(vw — cw) = Fn, 0 = FZ, (2.1)

0 = M,, 0 = Mn, Jw = MZ. (2.2)

The system (2.1)-(2.2) is closed relative to the variables v,w,Na,Nb,Nc and R. The reactions Nc and R can be expressed in terms of the reactions Na and NB (Nc can be expressed from the third equation of (2.1) and R from the second equation of (2.1) with the third equation of (2.2) taken into account):

Nc = mg — (Na + Nb ), (2.3)

R =

Jriwu) + k (riid2 — lib + c)) w ( —- + — ) — krnacv (

v va vb j v

NA , NB\ ,________(NB _ NA

vb Va

2

I-1, (2.4)

I = J + mc

The reactions Na and NB are uniquely defined from the system

(b + c)(NA + NB) + khv (— + — ) - Fir(v)h - khauj (— - — ) = mgc, (2.5)

\Va Vb J \Vb Va J

—IaiNs — Na) + riiackhv ( —- — —— ) — ml2ckhw ( —— + —- ) = Jriivuh, (2.6)

\Vb Va ) \ Va Vb J

which is obtained from the first two equations of (2.2) with (2.4) taken into account. Obviously,

the reactions Na, Nb (and hence Nc, R) depend only on the phase variables v, w and the system parameters.

We note that the solution of the system (2.5)-(2.6) must satisfy the conditions

Na > 0, Nb ^ 0, Na + Nb < mg, (2.7)

which ensure (along with conditions (2.3), (2.5), and (2.6)) that the body moves without loss of contact with the plane. Conditions (2.7) impose a restriction on the height of the center of mass of the body. Indeed, if we fix the mass and geometric parameters of the sleigh, except for h,

with b,c> 0, and take arbitrary w0,v0, then from Eqs. (2.5), (2.6) we obtain normal reactions NA(h),NB(h) as functions of height. It is obvious that

Na (0) = NB (0) =

mgc 2 (b + c)

(2.8)

and condition (2.7) is satisfied, with all inequalities being rigorous. But since Na(h),NB(h) are continuous at h = 0, conditions (2.7) will be satisfied also when yh G [0; h0) for some h0 depending on the initial velocities wo,vo. An example of normal reactions at the points of contact is given in Fig. 2.

Fig. 2. Reactions NA(t),NB (t),NC(t).

The set M = {(v, w) : T(v, w) ^ T(v0, w0)} is compact. Then such a value h0 can be chosen simultaneously for all (v,w) G M. Thus, there exists h0 > 0, which depends only the system parameters and the initial velocities v0,w0, such that, when h < h0, conditions (2.7) are satisfied for all values of v, w at which the corresponding kinetic energy does not exceed the initial one.

3. Equations of motion and properties of their solutions

Let h < h0. Then the motion of the Chaplygin sleigh on the horizontal plane with dry friction at the supporting points A and B is described by a second-order system relative to the phase variables of the problem, v and w.

mv + mew = —k--1--v + + k---auj, (3.1)

\VA vb J \VB va )

t 2 (NB Na\

lu — mcvuj = —k--1--lui + k---av. (3.2)

\va vb j \vb va j

These equations are obtained from the first equation of (2.1) and from the third equation of (2.2) with (2.3) and (2.4) taken into account, and Na(v,w) and NB(v,w) are defined from the system (2.5)-(2.6).

3.1. The case v = 0

We first consider the case of rest of the point of contact, C, of the knife edge. In this case, we set v = 0, V = 0. Then Eqs. (2.5), (2.6), (3.1), and (3.2) can be rewritten as

(b + c)(Na + NB) - eh - —¡—T—r(NB - NA) = mgc,

l |w|

-Ia(NB - Na) ~ >mlckh^-(NA + NB) = 0,

|w|

2 ka.^T „T . w

mcuj =d + —(NB-NA) — , l |w|

Iuj = -kl(NA + NB)^-, l w l

where ldl ^ kcNc. From the first three equations, with (2.3) taken into account, one can find conditions under which point C will remain at rest, as well as the values of d, Na, and NB.

Statement 1. The system (3.1), (3.2) admits an invariant set M = {(w,v) : v = 0,

w2 <

2 ^ g(Ibkc — mc2k2h)

cl (b + c) + mc2k2h2 + kc chl' Proof.

If v = 0 and V = 0, then va = vB = l|w|, hence Na = N0(1 + v),NB = N0(1 — v), where

mc(g + w2h) mlckh w

N0 = --v-) v ~

iНе можете найти то, что вам нужно? Попробуйте сервис подбора литературы.

2(b + c) ' Ia |w|

In this case,

2 m2c2k2h(g + w2 h)

1 = ma^ +-Hb + c) ■

In view of (2.3) the condition ^ ^ kcNc ^ is

2 < g{Ibkc - mc2k2h)

W " cl(b + c) + riic2k2h2 + kcchl' ( '

It should be noted that the set exists under the condition kc > mc^k. Consider the motion on the invariant set M. Given the previous statement, the equation Iuj = —kl(NA + NB)has the form

mlck(g + w2h) w

UJ =---.

I{b + c) M

Integrating it for w > 0, we obtain

19 ( I h \ mclk Jhg \ uj = \ — tan arctan 4 / — ujq--—-—t

\h ^ VV^ 7 J(6 + c) J

3.2. The case v = 0

Consider the instants of time when the velocity of the point of the skate, C, does not vanish. Statement 2. The system (3.1)-(3.2) is invariant under the change of w to -w. Proof.

In the case of this replacement, va and vB are interchanged. Consequently (see (2.5) and (2.6)), Na and NB are interchanged, i.e., the system (3.1)-(3.2) maps into itself.

Statement 3. The system (3.1)-(3.2) admits an invariant set w = 0 along which the motion of the Chaplygin sleigh is defined by the following relations for v0 > 0 and v0 < 0, respectively:

v(t) = vo - f G [0>i+]; i+ = ((b + e) +h(k -kc))vo^ (3 4)

(b + c) + h(k - kc) v(t) = v0 + 9<yCk "t ff^ . . t, ie[0,i_];i_ =

g(ck + bkc) ((b + c) - h(k - kc))M

(3.5)

(b + c) - h(k - kc) ' L ' _J' " g(ck + bkc)

(v0 = v(0); without loss of generality the initial instant of time is assumed to be zero). Proof.

When w = 0, Eq. (3.2) is satisfied identically for any v and Eq. (3.1) takes the form (see (2.8))

g(ck + bkc) v

v = —

b + c + {k-kc)h^ M

If v0 > 0, then v = -g(ck + bkc)(b + c + h(k - kc)) 1, and if v0 < 0, then v = g(ck + bkc)(b + + c - h(k - kc))_1, from which relations (3.4) and (3.5) follow immediately.

Remark 1. Obviously, t+ > t- k > kC, i..e., the translational motion of the Chaplygin sleigh during which the knife edge is ahead lasts longer than in the case where the knife edge is behind if and only if the coefficient of dry friction in the skate is less than the coefficients of friction in the legs (the absolute value of the initial velocity being the same).

Statement 4. The motion of the Chaplygin sleigh on a horizontal plane with dry friction at any initial values v0 and w0 which are not zero simultaneously ceases infinite time (if v0 = 0, w0 = 0, then v = 0,w = 0).

Proof.

It follows from the system (3.1)-(3.2) that

T = -kQ(v,w),

(3.6)

where T = js the kinetic energy,

(NA ^Nb kcNc\ 2 (NB Na\ (Na Nb\ , 2

Q =--1---h —,- ) v - 2 [---vauj +--1--I OJ .

v va vb kvc ) \vb va ) \va vb )

Obviously, the Q-homogeneous function is a function of degree 1 of phase variables v and w, and

q > 0 for any v and oj that are not zero simultaneously. Consequently, there exists a constant q > 0 such that Q ^ qVT. In this case, relation (3.6) takes the form

T =

dt

dt

= -kQ < -kqVT

2

and hence < i.e.,

<

(To

towo+zwo

2

that vT ^ 0, we conclude that the motion ceases in finite time to ^ ¡^

. Taking into account the fact

4. The phase portrait for h = 0

If h = 0 and v = 0, Eqs. (3.1) and (3.2) take the form

kgC v

v = -CIO2 - ———--V - kcNc-r-r, V = (vA + vB)v - (vA - vB)au),

2(b + c)vavb \v\

Id) = mcvu +

mkgc

2(b + c)vavb

Q, Q = (va — vB)av — (va + vB)l2d.

Obviously, the system (4.1)-(4.2) admits the solution (cf. (3.4), (3.5))

_ft ■ , xg(kc + bkc)

00 = 0, V = Vq Slgn(t'o)-7-,-1

b + c

t e [0,to], to =

(b + c)\vo\ \ g{kc + bkc)J

(4.1)

(4.2)

(4.3)

and, in particular, the solution d = 0, v = 0. An example of a phase portrait of the system is given in Fig. 5a.

The system admits motions along the phase trajectory d = 0. In this case, the trajectory of the skate and of the center of mass is a segment, and the system executes translational motion. If the value of the initial velocity of the skate v is nonzero, the motion of the sleigh can cease in the stagnation region (3.3). 2 cases can arise. If the initial value of \d\ is relatively small, velocity v decreases monotonically to zero and gets into the stagnation zone, and the system begins to rotate about a fixed vertical axis passing through the skate (Fig. 3a). The other case of motion is possible when the absolute value of the initial angular velocity is sufficiently large. Then, monotonically decreasing, velocity v reaches zero, but the phase curve does not get into the stagnation region, and the system starts moving back, after which the absolute value of velocity v increases for some time and then begins to decrease and the system arrives at the stagnation region (an example of the trajectory is given in Fig. 3b). In this case, the trajectory of the skate is a "beak" at the point where v = 0.

0.5 1.0

(a)

0.2 0.4 0.6 0.8 1.0 x

(b)

Fig. 3. Examples of trajectories.

Let us investigate the behavior of the phase curves in a neighborhood of an equilibrium point. We consider the case w > 0 and introduce a small parameter e and new variables:

2 v2 + (aw0)2 ~ , r v v

e2 = —--——, V = ev, w = ew, t = st, z = — = —. (4.4)

ag aw aw

Introducing the new notation ¿t2 = A = we rewrite Eqs. (4.1), (4.2) as

dv kgc A(z)z + B(z) kcgb , . . t .

— = -ecw2---r-—- v N v ' - -r^— sign(z), (4.5)

dt 2(b + c) W(z) b + c 6 v ;

d{cti) 2-2- kgc (1 + X2)A(z) + B{z)z dt Ct W ¿t2 2(6 + c)^ W(z) ' 1 j

where

x{z) = — sign(z), wa,b(z) = \J(1 ± z)2 + A2,

A(z) = №a(z) + WB (z), B (z) = WB (z) - wa(z), W (z) = wa(z)wb (z). Rescaling time as r = In re [0; +oo), we obtain dz B(z)z2 + (1 + A2 - |2)A(z)z - |2(B(z) + 2kW(z))

dr (1 + A2)A(z) + B(z)z

2|2(b + c)W(z) „2 -2T (1 + A2)A(z) + 2(B(z)z + kW(z)) + A(z)z2

(4.7)

22

— t ---u0e

kg 0 [(1 + A)2 A(z) + B (z)z)]2

Consider the first approximation of Eq. (4.8) in the small parameter e: dz B(z)z2 + (1 + A2 - |2)A(z)z - |2(B(z) + 2kW(z))

dr (1 + A2 )A(z) + B(z)z

= C (z). (4.8)

Obviously, the right-hand side of (4.8) is an odd function, and so, in what follows, we will consider only the case z > 0. It is also easy to verify that (1 + A2)A(z) + B(z)z > 0Vz.

iНе можете найти то, что вам нужно? Попробуйте сервис подбора литературы.

Let us check whether u = ^ = \ = 0 is a solution. Then, taking u ^ 0 into account, we

have

E(u) + (1 + A2 - Li2)F(u)u - V2 (E(u)u2 + UKF^a]-E^a])

D(u) =--hn-L

(l + X2)F(u) + ^

Here

E(u) = B (j-^j u, F(u) = A (j-^j u,

since

E{0) = 0, F{0) = 2, lim ^^ = -2 => £>(0) = 0. u^0 u

Thus, u = 0 is a solution, and since

|2(1 + k) - A2

E (0) = -2, F (0) = 0 ^ D (0) =

A

it follows that the solution u = 0 is unstable for i2 (1 + k) > A2 and asymptotically stable for ¡2(1 + k) < A2.

Let z = 0, u = 0. We will seek a solution to Eq. (4.8) of the form z = const:

B(z)z2 + (1 + A2 - ¡2)A(z)z - ¡2(B(z) + 2kW(z)) = 0 ^ ¡2 = f (z),

f (z) =

B (z)z2 + (1 + A2)A(z)z

A(z)z + B (z) +2kW (z)' Let us find f (z). To start with, we estimate the asymptotics of wa,b(z):

(4.9)

A2

2z2

1

A2

wA(z) = l + z + —-r + O ^r , wB(z) = -l + z + —^ + 0[^),z

2z2

1

.

Then

f, ^ A2 + 0(4Q f, ^ A2

1 + x + o 1

1 + K

The graph of the function f (z) has the form shown in Fig. 4.

1.61.41.210.80.60.40.20

0 5 10 15 20

z

Fig. 4. The graph ¡2 = f (z) for z > 0.

Thus, at a sufficiently large value of the coefficient kC and Vi > 0, in a neighborhood of the equilibrium point there is a solution z = 0 that is created by static friction forces at point C,

giving rise to sets of "stagnation" from Statement 1. For ¿t2 G (0; j^) there are also solutions

u = 0, z = z\, with u = 0 being asymptotically stable and z = z\ unstable. For ¿t2 G [j^] Mmax) there are solutions u = 0, z = zi, z = z2, z2 > z1, with u = 0, z = zi being unstable and z = zi asymptotically stable.

Examples of phase portraits are given in Fig. 5.

References

[1] Chaplygin, S. A., On the Theory of Motion of Nonholonomic Systems. The Reducing-Multiplier Theorem, Regul. Chaotic Dyn., 2008, vol.13, no. 4, pp. 369-376; see also: Mat. Sb., 1912, vol.28, no. 2, pp.303-314.

-2 0 2

(a) the initial system

(b) e = 0,

(c) e = 0, Ar G (îf^AW)

(d) £ = 0, /> / m

Fig. 5. Phase portraits for h = 0.

[2] Neimark, Ju. I. and Fufaev, N. A., Dynamics of Nonholonomic Systems, Trans. Math. Monogr., vol. 33, Providence, R.I.: AMS, 1972.

[3] Levi-Civita, T., Sulla stabilita delle lavagna a cavalletto, Periodico de Mathematiche (4), 1924, vol. 4, pp. 59-73.

[4] Karapetyan, A. V. and Shamin, A. Yu. On the Movement of the Chaplygin Sleigh on a Horizontal Plane with Dry Friction, J. Appl. Math. Mech, 2019, vol. 83, no. 2, pp. 251-256; see also: Prikl. Mat. Mekh, 2019, vol. 83, no. 2, pp. 228-233.

[5] Ivanov, A. P., Fundamentals of the Theory of Systems with Friction, Moscow-Izhevsk: R&C Dynamics, Institute of Computer Science, 2011 (Russian).

[6] Sumbatov, A. S. and Yunin, E.K., Selected Problems of Mechanics of Systems with Dry Friction, Moscow: Fizmatlit, 2013 (Russian).

[7] Kuleshov, A.S., Treschev, D. V., Ivanova, T.B., and Naimushina, O.S., A Rigid Cylinder on a Vis-coelastic Plane, Nelin. Dinam., 2011, vol.7, no. 3, pp. 601-625 (Russian).

i Надоели баннеры? Вы всегда можете отключить рекламу.