Научная статья на тему 'On solvability of one difference equation'

On solvability of one difference equation Текст научной статьи по специальности «Математика»

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DIFFERENCE EQUATIONS / HAMEL BASIS / PATHOLOGICAL SOLUTIONS / EXISTENCE AND UNIQUENESS

Аннотация научной статьи по математике, автор научной работы — Chernov I. A.

We consider a system of difference equation similar to those that appear as description of cumulative sums. Using Hamel bases, we construct pathological solutions to this system for constant right-hand sides. Also we show that bounded solutions do not exist for non-zero right-hand sides, while only constants can be solutions in the homogeneous case.

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Текст научной работы на тему «On solvability of one difference equation»

Probl. Anal. Issues Anal. Vol. 6(24), No. 1, 2017, pp. 41-45

41

DOI: 10.15393/j3.art.2017.3550

UDC 517.929.2

I. A. Chernov

ON SOLVABILITY OF ONE DIFFERENCE EQUATION

Abstract. We consider a system of difference equation similar to those that appear as a description of cumulative sums. Using Hamel bases, we construct pathological solutions to this system for constant right-hand sides. Also we show that bounded solutions do not exist for non-zero right-hand sides, while only constants can be solutions in the homogeneous case.

Key words: difference equations, Hamel basis, pathological solutions, existence and uniqueness

2010 Mathematical Subject Classification: 39A06

1. Introduction. Let z > 0 and b > z + 1 be some real numbers. We consider functions js = j(s) on [0, b], s is the independent variable. Let p > 0, q > 0, p + q =1be real numbers. We consider the following system of difference equations:

Here rs is some function of s. Similar systems describe dynamics of cumulative sums [2, 4]. We studied a system of this kind in [3]. However, (1)-(3) is different: the factor at j in the right-hand side of (1) and (3) is 1, not p or q. This system describes special cases of random walk in a band when the walking particle is repelled from the boundaries.

We are going to study existence and uniqueness of a solution to this system. We show that there are multiple solutions provided that z is irrational, but these solutions are quite pathological and hardly can be used in any application.

js = js+z + rs,

js = pjs-1 + qjs+z + rs ,

js = js-1 + rs,

s < 1, 1 < s < b - z, b — z < s < b.

(1) (2) (3)

©Petrozavodsk State University, 2017

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2. Operator form of the system. Let us define operator T by

Tjs = js+z, s < 1, (4)

Tjs = pjs-1 + qjs+z, 1 < s < b — z, (5)

Tjs = js-i, b - z < s < b, (6)

and operator F as E — T with E as the identity. Now the equation can be written as Fj = r or j — Tj = r.

Now let us note that any constant function is an eigenfunction of T for the eigenvalue 1. Also any constant function belongs to the core of F. Therefore the solution js to the problem, if one exists, is not unique: js + const is also a solution. However, the problem Fjs = rs may lack solutions for some right-hand sides rs.

Solutions to the problem with rs = const, if exist, possess some kind of self-similarity:

Theorem 1. If js is a solution to Fjs = c, c = const, then Tjs is also a solution.

Proof. Operators T and F = E — T commute; so, Fj = c implies TFj = = Tc = c and, due to commuting, FTj = c. □

3. Bounded solutions. Let us show that for positive right-hand sides there are no bounded solutions.

Theorem 2. System (1)-(3) has no bounded solutions provided that rs > r > 0.

Proof. First assume that j* = j(s *) is the minimal value of js on [0, b]. If 1 < s * < b — z, then, due to (2),

* * i i \ i i H« i

j = Js* = pjs*-i + qjs* +z + rs* > PJ + qj + r = j + rs* >J ,

which is a contradiction. The similar contradiction appears if we assume that s > b— z or s < 1. This means that a solution, if it exists, does not have the minimal value. Let us consider the case of a bounded solution with no minimum.

As the solution is bounded, js > B for some B; let B be the infimum, so that for any e > 0 js < B + e in at least one s.

Choose a positive e < 1 and find a j * = js* < B + e. Then in the similar way get j * > B + r which contradicts j * < B + e < B + r. □

The similar argument shows that in the homogeneous case rs = 0 continuous solutions are only constants provided that z is irrational.

Theorem 3. Let z be irrational and rs =0 for all s G [0, b]. Then if js is a continuous solution to (1)-(3), js = const.

Proof. Indeed, a continuous function on a segment must have maximal and minimal values; if j * = js* is the minimum, then js*+z = js*-1 = = j . Continue this argument to see that js = j on a dense countable subset of [0, b]. It is dense because it consists of points s * + Qz — P with integers P, Q > 0 and Dirichlet's approximation theorem guarantees approximation of any point of [0, b] with arbitrary precision. By continuity js is constant on [0, b]. □

Obviously the problem can have solutions for specially chosen rs; in fact for rs = Fjs for any chosen js. The proved result yields a corollary:

Corollary. For any function js its image rs = Fjs cannot be "absolutely positivefor any e > 0 rs — e < 0 in some s. Also it cannot be "absolutely negative".

Here is another proof for constant right-hand sides.

Theorem 4. Bounded solutions to Fj = 1 do not exist.

Proof. Note that T does not decrease the upper bound of its argument: if js > M, Tjs > M. This is easily checked directly. Now, let js be a bounded solution to Fj = 1: Tjs = js — 1. This decreases the upper bound of js and thus provides a contradiction. □

Let us consider the case of a rational z. Choose any s G [0, b] and consider the set U of all points s + mz + n G [0, b] with integer n and m. The smallest possible distance between these points is bounded from below by N-1 where N is the smallest natural in z = M/N (M is also natural). So the set U is finite. Operators T and F transform U into U and therefore are linear finite dimensional mappings. Matrix T is degenerate. The results proved above can be made stronger:

Theorem 5. Let z be rational. System (1)-(3) has no bounded solutions provided that rs > 0 (or rs < 0). For rs =0 solutions are constant at any U.

Proof. Proof of theorem 2 remains valid for the considered case. Minimal value is obtained in some point of any U. The only difference is possibility

of minimal value at some s* with rs* = 0. But then js*-i and js*+z are also minimal (provided that the arguments belong to [0,b]). Then rs = 0 also in these points. Continue to prove that rs = 0 in all s G U for any U, so that rs = 0 everywhere. In this case solution exists, but is constant on any U; though, it can be different for different sets U with no common points. □

4. The Hamel solutions. Now let us construct a solution for the special case rs = 1. Choose any Hamel basis on R1 that contains 1 and z. This is a set H of real numbers, (1, z G H) such that any x G R1 is a finite linear combination of numbers from H with rational coefficients. It is known [1] that such basis exists if the lemma of choice is accepted. Let us denote the coefficient at h G H for expansion of x by x<h).

Consider the function js = s<^ — s<z). Substitute it to (2):

s<1) — s(z) = s(i) — (s<z) + 1) + 1, s < 1,

s<i) — s<z) = p(s<1) — 1 — s<z)) + q(s<1) — (s<z) + 1)) + 1, 1 < s < b — z, s<1) — s<z) = s<1) — 1 — s<z) +1, b — z < s < b,

which is true. So the constructed function indeed is a soluton, together with any js + const.

In the homogeneous case rs = 0 any js = s<h) is a solution for any h G H except 1 and z.

Let us note a few points as a conclusion.

• Although we have constructed numerous solutions to the system with special right-hand sides, they are pathological and thus hardly useful, being discontinuous in every point, unbounded in any neighbourhood of each point, and having only rational values in all points. It is hardly possible to evaluate the solution, except for special points.

• In rational points s the constructed solution js = s; however, js = s for any s is not a solution.

• For practical purposes it is sufficient to evaluate the solution in points Pz — Q for integer P, Q > 0: jpz-Q = Q — P.

• For different Hamel bases we get the same solutions; however, there are different solutions (up to adding a constant) for the same Hamel basis: js + s<h) is obviously a solution for any h G H except 1 and z, provided that js is a solution.

• Choosing any rational number instead of 1 in H provides different solutions; this can be used to provide desired properties of solutions. The same is true for replacing z by az for a rational a.

• Existence of such solutions in the case of non-constant right-hand sides is still an open question.

References

[1] Kuczma M. An introduction to the theory of functional equations and inequalities. Cauchy's equation and Jensen's inequality. Basel: Birkh auser, 2009.

[2] Mazalov V. V., Nikitina N. N. A CUSUM Method to Detect and Counteract Intrusions. Programming and Computer Software, 2014, vol. 40, no. 6, pp. 337-345.

[3] Nikitina N. N., Chernov I. A. Solvability of system of difference equations for dynamics of cumulative sum. Probl. Anal. Issues Anal, 2014, vol. 2(21), no. 2, pp. 59-73. In Russian. DOI: 10.15393/j3.art.2013.2384

[4] Page E. S. Continuous Inspection Schemes. Biometrika, 1954, vol. 41, pp. 100-114.

Received December 30, 2016.

In revised form, March 13, 2017.

Accepted April 5, 2017.

Published online May 24, 2017.

Inst. Appl. Math. Research of Karelian Research Centre of Russian Academy

of Sciences, 11, Pushkinskaya st., Petrozavodsk 185910, Russia;

Petrozavodsk State University

33, Lenina pr., Petrozavodsk 185910, Russia

E-mail: [email protected]

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