Научная статья на тему 'MURAKKAB ARGUMENTLI TRIGONOMETRIK TENGLAMALARNI YECHISH'

MURAKKAB ARGUMENTLI TRIGONOMETRIK TENGLAMALARNI YECHISH Текст научной статьи по специальности «Гуманитарные науки»

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Ключевые слова
trigonometric equations / complex arguments / lowering the degree. / trigonometric equations / complex arguments / lowering the degree.

Аннотация научной статьи по Гуманитарные науки, автор научной работы — Azizjon B.K

There are multiple standard and non-standard methods for solving trigonometric equations, and these methods can vary significantly. Solving trigonometric equations with complex arguments often presents a greater challenge for students. Even when they manage to solve the equation, they may struggle to identify the key elements of the solution. Addressing these challenges by incorporating the study of solving such equations and inequalities into both mathematics circles and faculty training is crucial.

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SOLVING TRIGONOMETRIC EQUATIONS WITH COMPLEX ARGUMENTS

There are multiple standard and non-standard methods for solving trigonometric equations, and these methods can vary significantly. Solving trigonometric equations with complex arguments often presents a greater challenge for students. Even when they manage to solve the equation, they may struggle to identify the key elements of the solution. Addressing these challenges by incorporating the study of solving such equations and inequalities into both mathematics circles and faculty training is crucial.

Текст научной работы на тему «MURAKKAB ARGUMENTLI TRIGONOMETRIK TENGLAMALARNI YECHISH»

Azizjon B.K.

Qo 'qon davlat pedagogika instituti talabasi

MURAKKAB ARGUMENTLI TRIGONOMETRIK TENGLAMALARNI

YECHISH

Annotation. There are multiple standard and non-standard methods for solving trigonometric equations, and these methods can vary significantly. Solving trigonometric equations with complex arguments often presents a greater challenge for students. Even when they manage to solve the equation, they may struggle to identify the key elements of the solution. Addressing these challenges by incorporating the study of solving such equations and inequalities into both mathematics circles andfaculty training is crucial.

Keywords: trigonometric equations, complex arguments, lowering the degree.

Azizjon B.K. student

Kokand State Pedagogical Institute

SOLVING TRIGONOMETRIC EQUATIONS WITH COMPLEX

ARGUMENTS

Annotation. There are multiple standard and non-standard methods for solving trigonometric equations, and these methods can vary significantly. Solving trigonometric equations with complex arguments often presents a greater challenge for students. Even when they manage to solve the equation, they may struggle to identify the key elements of the solution. Addressing these challenges by incorporating the study of solving such equations and inequalities into both mathematics circles andfaculty training is crucial.

Keywords: trigonometric equations, complex arguments, lowering the degree.

1-misol. Ushbu

sin(sin(cos x - sin x)) = 0

tenglamani yeching. [l]

Yechish: sin(cosx - sinx) = 7n, n g Z. -1 < sin t < 1 bo'lgani uchun -1 <7n < 1 bo'lishi kerak. Bundan n = 0. Endi sin(cosx - sinx) = 0tenglamani yechamiz. Bu cos x - sin x = 7k, k g Z tenglamaga teng kuchli.

sin(x) = *^2—к . к ning qiymati -l<—= < l tengsizlikni

ж

qanoatlantirishi kerak, bundan к = О. Demak, sin(x - — ) = О tenglamani yechamiz. x = — + —m, m e Z

Javob: — + —m,m e Z. 4

2-misol. Ushbu

cos(—Vl - sin x ) = l

tenglamani yeching. [l]

Yechish: V'l - sin x = 2к, к e N0 bo'lishi keгak.U holda sinx = l - 4к2,

-l < sin x < l bo'lgani uchun -l < l - 4к2 < l, -2 < -4к2 < О; О < к2 < l.

Demak, к = О va sinx = l.

Javob:— + —n, n e Z. 2

3-misol. Ushbu

sin2(l - cos x) = cos2(l + cos x) tenglamani yeching. [2]

Yechish. Darajani pasaytirish foгmulasini qo'llab

cos(2 + 2 cos x) + cos(2 - 2 cos x) = О tenglamani hosil qilamiz. Kosinus^ yig'indisini ko'paytmaga o'tkazib

cos(2cosx) = О; cosx = —+ —n, n e Z ni hosil qilamiz. n ning qabul qilishi

ж —n

mumkin bo'lgan qiymatlaгini topish uchun -l < — + — < l tengsizlikni

i i —

yechamiz. Bundan n = О yoki n = - l. Demak, |cos x| = —

Javob: + arccos —+ —к, к e Z. 4

4-misol. Ushbu

cos x + cosVx = 2

tenglamani yeching. [l]

Yechish: \cosx\ < l va |co^Vx < l bo'lgani uchun berilgan tenglama quyidagi sistemaga teng kuchli

cosx = 1 Г x = 2лк, к е Z cos Vx = 1 ' [x = 4л2m2,m е Z

Bundan 2лк = 4л2m2;к = 2лт2, к va m lar butun son bo'lganligi uchun oxirgi tenglik к = m = 0 da o'rinli.

Javob:0

5-misol. Ushbu

cos Vx = cosV x +1

tenglamani yeching. [2]

Yechish: Berilgan tenglama quyidagi tenglamaga teng kuchli. . Vx - Vx + 1 Vx + Vx + 1 л

- 2 sin-sin-= 0

2 2

. Vx+Г-yfx . Vx +V x + 1 . Bundan sin---= 0 ; sin---= 0. x ni topish uchun

quyidagi 2 ta tenglamani yechamiz. Vx +1 -л/x = 2лк, к е N; •ч/x + V x +1 = 2лп,п е N;

x > 0 da Vx +1 - Vx > 0 bo'lganligi uchun к е N

x > 0 da Vx + Vx +1 > 0 bo'lganligi uchun к е N.

Birinchi tenglamani yechamiz. x +1 = x + 4лky¡x + 4л:2 к2 ;

4лк^л = 1 - 4л2 к2

Bu tenglama к е N da yechimga ega emas.Ikkinchi tenglamani yechamiz. Vx = 2лп- V x +1. Bu tenglama quyidagi sistemaga teng kuchli.

x = 4л2n2 - 4лnVx +1 + x +1; 2лп > vx +1

Sistemaning birinchi tenglamasidan Vx +1 = 4л n +1

4лп

Vx +1 < 2лп,(п е N ) ekanligini ko'rsatamiz.Haqiqatan ham,

4л2 n2 +1 „ -4л2 n2 +1 л

-< 2лп; -< 0

4лп 4лп

Oxirgi tengsizlik n е N da o'rinli.

__ , ,4л2п2 +V2 ,4Л2П2 -1.2

Demak, x = (-)2 -1 = (-)2, n е N

4лп 4лп

. ,4л2п2 -12

Javob:, (-)2, n е N

4лп

Foydalanilgan adabiyotlar:

1. Севрюков П.Ф., Смоляков А.Н. Тригонометрические, показательные и логарифмические уравнения и неравенства. Москва.Ставрополь 2008.

2. Моденов В.П Математика. Пособие для поступающих в вузы. Москва. Новая волна. 2002.

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